Posted by Leslie on Sunday, September 26, 2010 at 1:08pm.
Do you have any thinking on these? Surely you do not want us to give you answers.
1. X^2= 4Y^2 and x=2y+1
Sooo i substitute
(2y+1)^2= 4y^2
Find the square root of both sides
2y+1= 4y
Solve for y
2y+1=4y
1=4y
.25=y
Substitue into X=2y=1
x=2(.25)+1
x=.5+1
x=1.5
But thats not an option.What did i do wrong?
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