Sunday

February 1, 2015

February 1, 2015

Posted by **Anonymous** on Sunday, September 26, 2010 at 12:07pm.

2-FOR what values of A the equation has no solution ax ² +3 x-7 = 0

3-For what values of x the equation has 2 solution X²-X+C=0

4-Solve the equation (X-1)²-4=0

5-Solve the equation a)2/2 x^(-3)=2√2

b)3^(x^2-2x)=27

c)5/25 x^(+3)=5√5

help me with the solution of this equations please

- math -
**MathMate**, Sunday, September 26, 2010 at 12:57pm1.

Factor the equation to

(x-3)(x+2)=0

So the roots are 3 and -2.

Calculate the sum of roots.

2.

A quadratic equation ax²+bx+c=0 has no real roots when the discriminant is less than zero, that is:

b²-4ac<0

For the present case,

b=3, c=-7

Solve for the inequality in terms of a.

3. and up

Please show some work to indicate where you have difficulties.

- math -
**Anonymous**, Sunday, September 26, 2010 at 1:20pma)2/2 x^(-3)=2√2

b)3^(x^2-2x)=27

c)5/25 x^(+3)=5√5

i have difficulties with this three equations

- math -
**MathMate**, Sunday, September 26, 2010 at 2:14pma)

2/(2x^(-3))=2√2

2/(2x^(-3)) = 2√2/1

Cross multiply to get:

2*1 = (2√2)*(2x^(-3))

1=2√2/x³

Cross multiply again:

x³=2√2

x³=(√2)³

Can you take it from here?

b)

3^(x^2-2x)=27

3^(x^2-2x)=3³

therefore

(x^2-2x)= 3

Solve for x by factoring

x²-2x-3=0

(x-3)(x+1)=0

...

c)

similar to a).

Post your answer for checking if you wish.

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