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What are the values of b which satisfy b- square root of 1-1996b=1?

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    b - sqrt(1 - 1996b) = 1,
    Isolate the radical:
    b - 1 = sqrt(1 - 1996b),
    Square both sides:
    b^2 - 2b + 1 = 1 - 1996b,
    b^2 - 2b + 1996b = 1 - 1,
    b^2 + 1994b = 0,
    Factor out b:
    b(b + 1994) = 0,
    b = 0,
    b + 1994 = 0,
    b = -1994,

    Solution set: b = 0, and b = -1994.

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