Post a New Question


posted by .

A ball is thrown horizontally from a 15m -high building with a speed of 8.0m/s. How far away from the base of the building does the ball hit the gnd. I'm needing help setting this up. I know change of Y is -15m, and the "a" is -9.8m/s^2, but i get lost from there...?

  • physics -

    Using h = Vot + 9.8t^2/2
    15 = 0(t) + 4.9t^2 yields t = 1.75 sec to impact.
    During this 1.75 sec., the ball travels 1.75(8) = 14m horizontally from the base of the building.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question