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January 18, 2017
Posted by **flame** on Sunday, September 26, 2010 at 1:24am.

am i allowed to rearrange this to d^2y/dx^2-dy/dx=1 and say this is a linear ODE

- math -
**MathMate**, Sunday, September 26, 2010 at 2:36pmUsing the notation

y"=d²y/dx², and

y'=dy/dx,

you can write

y"=1-y'

as

y"+y'=1, or

y"+y'-1=0

It is a linear ODE because the terms of the dependent variable, y, y', y", ... are linear in*y*, i.e. no terms contains (y")², or y³, etc.