math
posted by flame on .
d^2y/dx^2=1dy/dx
am i allowed to rearrange this to d^2y/dx^2dy/dx=1 and say this is a linear ODE

Using the notation
y"=d²y/dx², and
y'=dy/dx,
you can write
y"=1y'
as
y"+y'=1, or
y"+y'1=0
It is a linear ODE because the terms of the dependent variable, y, y', y", ... are linear in y, i.e. no terms contains (y")², or y³, etc.