three point charges are located at the corners of a right triangle where q1=q3= 5uC,Q2= -2uC and r =10cm.(angle q1 q2q3=90 and q1q3=r)
To calculate the electric force between the point charges, you can use Coulomb's Law, which states that the magnitude of the electric force between two point charges is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them.
Coulomb's Law equation: F = k * (|q1| * |q2|) / r^2
Where:
F is the magnitude of the electric force
k is the electrostatic constant (k = 9 × 10^9 Nm^2/C^2)
|q1| and |q2| are the magnitudes of the charges
r is the distance between the charges.
In this case, we have three point charges at the corners of a right triangle. Let's label the charges as follows:
q1 (5 uC) P
|\
| \ q3 (5 uC)
| \
|___\
q2 (-2 uC)
Given:
q1 = q3 = 5 uC
q2 = -2 uC
r = 10 cm = 0.1 m
1. Calculate the force between q1 and q2:
F1 = k * (|q1| * |q2|) / r^2
= 9 × 10^9 Nm^2/C^2 * (5 × 10^(-6) C * 2 × 10^(-6) C) / (0.1 m)^2
2. Calculate the force between q2 and q3:
F2 = k * (|q2| * |q3|) / r^2
= 9 × 10^9 Nm^2/C^2 * (2 × 10^(-6) C * 5 × 10^(-6) C) / (0.1 m)^2
To find the net force, we need to consider both the magnitude and direction of the forces. Since q1 and q2 are opposite in sign, their forces would be attractive, whereas the force between q2 and q3 would be repulsive due to their similar signs.
The net force can be calculated using vector addition, considering the magnitudes and directions of the forces.
Net force = √(F1^2 + F2^2 + 2 * F1 * F2 * cosθ)
Where θ is the angle between the forces F1 and F2.
Given that the angle between q1 and q2 is 90 degrees, we can substitute the values and calculate the net force.