2(m^2+5n)-4n^3+9 for m=-5 and n=-2
answer= 95
i think this is the answer
2m^2+10n-4n^3+9=95
2(-5)^2+10(-2)-4(-2)^3+9=95
2(25)-20-4(-8)+9=95
50-20+32+9=95
30+41=95
71=95
95-71=24
i hope it was helpful
2(m^2 + 5n) -4n^3 + 9 =
2(-5^2 + 5*-2) -4*-2^3 + 9 =
2(25 - 10) -4*-8 + 9 =
2*15 + 32 + 9 =
30 + 32 + 9 = 71.
which 1 is rite
so the answer in the back of the book is 95?
how is the answer 95? i got 71
To find the value of the expression 2(m^2 + 5n) - 4n^3 + 9 for m = -5 and n = -2, we substitute the given values into the expression and evaluate it step by step.
First, let's substitute m = -5 and n = -2 into the expression:
2((-5)^2 + 5(-2)) - 4(-2)^3 + 9
Simplifying inside the parentheses:
2(25 - 10) - 4(-8) + 9
Further simplifying:
2(15) + 32 + 9
Next, perform the multiplication:
30 + 32 + 9
Add the numbers:
30 + 32 + 9 = 71
So, the value of the expression 2(m^2 + 5n) - 4n^3 + 9, for m = -5 and n = -2, is 71.