# Math Reiny question

posted by
**Sabrina**
.

This is the problem you helped me with. I was curious, do I write the solution set as (1 + i3ã3)/2,

(1-i3ã3)/2

change it to the standard form first

x^2 - x + 7 = 0

a=1, b=-1, c = 7

x = (1 } ã(1 - 4(1)(7))/2

= (1 } ã-27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as

x = (1 } 3ã3 i)/2