Posted by **Sabrina** on Friday, September 24, 2010 at 10:36pm.

This is the problem you helped me with. I was curious, do I write the solution set as (1 + i33)/2,

(1-i33)/2

change it to the standard form first

x^2 - x + 7 = 0

a=1, b=-1, c = 7

x = (1 } (1 - 4(1)(7))/2

= (1 } -27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as

x = (1 } 33 i)/2

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