Posted by **Allie** on Friday, September 24, 2010 at 10:07pm.

The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.

I have so far

let one leg be x

the other leg will be x-10

x^2 +(x-10)^2=22^2

x^2+x^2-20x+100=484

- Math word problem -
**Reiny**, Friday, September 24, 2010 at 10:23pm
carry on ...

x^2+x^2-20x+100=484

2x^2 - 20x - 384 = 0

x^2 - 10x - 192 = 0

I used the formula to solve for x

x = 19.7309

one side is 19.7309, the other 9.7309

- Math word problem -
**Ron**, Friday, September 24, 2010 at 10:30pm
x^2+x^2-20x+100=484

--> 2x^2-20x-384=0

--> x^2-10x-192=0

Now apply quadratic formula.

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