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posted by Allie on Friday, September 24, 2010 at 10:07pm.

The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs. I have so far let one leg be x the other leg will be x-10 x^2 +(x-10)^2=22^2 x^2+x^2-20x+100=484

carry on ... x^2+x^2-20x+100=484 2x^2 - 20x - 384 = 0 x^2 - 10x - 192 = 0 I used the formula to solve for x x = 19.7309 one side is 19.7309, the other 9.7309

x^2+x^2-20x+100=484 --> 2x^2-20x-384=0 --> x^2-10x-192=0 Now apply quadratic formula.

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