Posted by Allie on Friday, September 24, 2010 at 10:07pm.
The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.
I have so far
let one leg be x
the other leg will be x10
x^2 +(x10)^2=22^2
x^2+x^220x+100=484

Math word problem  Reiny, Friday, September 24, 2010 at 10:23pm
carry on ...
x^2+x^220x+100=484
2x^2  20x  384 = 0
x^2  10x  192 = 0
I used the formula to solve for x
x = 19.7309
one side is 19.7309, the other 9.7309

Math word problem  Ron, Friday, September 24, 2010 at 10:30pm
x^2+x^220x+100=484
> 2x^220x384=0
> x^210x192=0
Now apply quadratic formula.
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