Math SCREAMING for HELP
posted by Sabrina .
Use the quadratic formula to slove the equation.
x^2x=7
This is what I have got so far and I do not think this is right:
x=1(1)±√1^24(1)(7)/2(1)
x=1±√14(7)/2
x=1±√21/2
x=1±21/2
and here I am lost!
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change it to the standard form first
x^2  x + 7 = 0
a=1, b=1, c = 7
x = (1 ± √(1  4(1)(7))/2
= (1 ± √27)/2
Your answer is an imaginary number or called a complex number, you could rewrite is as
x = (1 ± 3√3 i)/2 
x^2x+7=0
x= (1+sqrt(128))/2=1/2 + 1/2 sqrt21
and sqrt21= isqrt21
2) I don't understand the others. 
Okay so do I write the answer as the solution set is:(1 } 3ã3 i)/2 , 0