Math SCREAMING for HELP
posted by Sabrina on .
Use the quadratic formula to slove the equation.
x^2x=7
This is what I have got so far and I do not think this is right:
x=1(1)±√1^24(1)(7)/2(1)
x=1±√14(7)/2
x=1±√21/2
x=1±21/2
and here I am lost!
Use rational exponents to simplify. √(5&x^10 )
Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. ∛(〖125x〗^11/y^3 )
Multiply. (2t)^2 (〖3t〗^7 )²
Divide and simplify. (3y6)/14÷(y2)/4y

change it to the standard form first
x^2  x + 7 = 0
a=1, b=1, c = 7
x = (1 ± √(1  4(1)(7))/2
= (1 ± √27)/2
Your answer is an imaginary number or called a complex number, you could rewrite is as
x = (1 ± 3√3 i)/2 
x^2x+7=0
x= (1+sqrt(128))/2=1/2 + 1/2 sqrt21
and sqrt21= isqrt21
2) I don't understand the others. 
Okay so do I write the answer as the solution set is:(1 } 3ã3 i)/2 , 0