Homework Help: Math SCREAMING for HELP

Posted by Sabrina on Friday, September 24, 2010 at 9:19pm.

Use the quadratic formula to slove the equation.
x^2-x=-7
This is what I have got so far and I do not think this is right:
x=1(-1)▒√-1^2-4(1)(7)/2(1)
x=1▒√1-4(7)/2
x=1▒√-21/2
x=1▒-21/2
and here I am lost!

Use rational exponents to simplify. √(5&x^10 )

Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. ∛(〖125x〗^11/y^3 )

Multiply. (-2t)^2 (〖3t〗^7 )▓

Divide and simplify. (3y-6)/14ў(y-2)/4y

Math SCREAMING for HELP - Reiny, Friday, September 24, 2010 at 9:46pm
change it to the standard form first

x^2 - x + 7 = 0
a=1, b=-1, c = 7

x = (1 ▒ √(1 - 4(1)(7))/2
= (1 ▒ √-27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as
x = (1 ▒ 3√3 i)/2
Math SCREAMING for HELP - bobpursley, Friday, September 24, 2010 at 9:47pm
x^2-x+7=0

x= (1+-sqrt(1-28))/2=1/2 +- 1/2 sqrt-21

and sqrt-21= isqrt21

2) I dont understand the others.
Math SCREAMING for HELP - Sabrina, Friday, September 24, 2010 at 10:03pm
Okay so do I write the answer as the solution set is:(1 Б} 3Бу3 i)/2 , 0

Answer this Question

Related Questions

math - (4.35E-2 - x)(7.56E-2 -x ) ============================ (0.324 + 2x)2 ...
Math - Use the quadratic formula to solve each of the following quadratic ...
Algebra - For this equation x^(2) + x + 2 which you can't factor but then ...
Chemistry - Hmm... This does not make sense. I learned that anything over 5% ...
math,algebra - can someone help me out factor out this 0=16t^2-122t+180 i have ...
Math - Find the real solutions, if any, to this equation. Use the quadratic ...
math - quadratic equation of 48x^2-32x-35=0 i need both answers you must use the...
algebra - Solve the quadratic equation: 2x(squared)+6x+12=0 I know you have to ...
math-calculus - solve equation |x^2-2x-6| using quadratic formula. i not get how...
math - use the quadratic formula to solve this equation. 4x^2-8x+3=5 use the ...

For Further Reading

First Name:
School Subject:
Answer: