Posted by **Sabrina** on Friday, September 24, 2010 at 9:19pm.

Use the quadratic formula to slove the equation.

x^2-x=-7

This is what I have got so far and I do not think this is right:

x=1(-1)±√-1^2-4(1)(7)/2(1)

x=1±√1-4(7)/2

x=1±√-21/2

x=1±-21/2

and here I am lost!

Use rational exponents to simplify. √(5&x^10 )

Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. ∛(〖125x〗^11/y^3 )

Multiply. (-2t)^2 (〖3t〗^7 )²

Divide and simplify. (3y-6)/14÷(y-2)/4y

- Math SCREAMING for HELP -
**Reiny**, Friday, September 24, 2010 at 9:46pm
change it to the standard form first

x^2 - x + 7 = 0

a=1, b=-1, c = 7

x = (1 ± √(1 - 4(1)(7))/2

= (1 ± √-27)/2

Your answer is an imaginary number or called a complex number, you could rewrite is as

x = (1 ± 3√3 i)/2

- Math SCREAMING for HELP -
**bobpursley**, Friday, September 24, 2010 at 9:47pm
x^2-x+7=0

x= (1+-sqrt(1-28))/2=1/2 +- 1/2 sqrt-21

and sqrt-21= isqrt21

2) I don't understand the others.

- Math SCREAMING for HELP -
**Sabrina**, Friday, September 24, 2010 at 10:03pm
Okay so do I write the answer as the solution set is:(1 } 3ã3 i)/2 , 0

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