Posted by Sarah on .
a cubic piece of uranium metal (specific eat capacity= .117 J/g degree celcius) at 200.0 degrees celcius is droped into 1.00 L of deuterium oxide ("heavy water", specific heat capacity=4.211 J/g degree celcius) at 25.5 degrees celcius. the final temperature of the uranium and deuterium oxide mixture is 28.5 degrees celcius. Given the densities of uranium (19.05 g/cm cubed) and deuterium oxide (1.11 g/mL), what is the edge length of the cube of uranium?

ap chemistry 
DrBob222,
[mass U x specific heat U x (TfinalTinitial)] + [mass water x specific heat water x (TfinalTintial)] = 0
Use density D2O to determine mass heavy water.
Solve for mass U, then use density to calculate volume. Take the cube root of the volume to determine the edge length.Note the correct spelling of celsius. 
ap chemistry 
Perri_ppl,
THX!!!!