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March 30, 2015

Posted by **Sabrina** on Friday, September 24, 2010 at 6:07pm.

- Math HELP! -
**Reiny**, Friday, September 24, 2010 at 6:25pmI answered some of them

click on your name above and you will see your posts

- Math HELP! -
**Sabrina**, Friday, September 24, 2010 at 6:41pmThank you Reiny so much for you help. Can you tell me if I am on the right track with this problem: 4c^2/4c^2-8c+4 x 4c-4/2c When solving this am I supposed to find the gcf or lcm to solve> would the lcm be 2 and the gcf be 16? I don't know if I am even going down the right road here?

- Math HELP! -
**Reiny**, Friday, September 24, 2010 at 7:11pmUse brackets to show when the denominator ends

I think you meant

4c^2/(4c^2-8c+4)( 4c-4)/2c , which is

= 4c^2/(4(c^2 - 2c + 1)(4)(c-1)/(2c)

= 4c^2/(4(c- 1)^2(4)(c-1)/(2c)

now things cancel rather nicely

final result

2c/(c-1) , c ≠ 1,0

- Math HELP! -
**Sabrina**, Friday, September 24, 2010 at 7:35pmTHANKS!!!!!! Just one question, when I follow these steps and get to the result is it both 2c/(c-1), c 10 or am I reading my problem wrong and the answer is just c 10

- Math HELP! -
**Reiny**, Friday, September 24, 2010 at 9:38pmThe final answer is

2c/(c-1)

the part after it is the restriction.

you are reading it wrong, it does not have 10 in it.

it says, c cannot be equal to 1 or c cannot be equal to 0

Since we cannot divide by zero, those values would make the denominators we canceled equal to zero.

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