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December 22, 2014

December 22, 2014

Posted by **Jose** on Friday, September 24, 2010 at 11:17am.

- Math -
**unknown**, Friday, September 24, 2010 at 11:58amwork done = (actual time worked) / (req'd time to finish a task)

'completed' work = 1

so let

A = time req'd for A

B = time req'd for B

C = time req'd for C

there will be 3 equations:

(8/3A) + (8/3B) = 1

(40/9B) + (40/9C) = 1

(20/7A) + (20/7C) = 1

use elimination method to solve the problem.

- Math -
**Jose**, Friday, September 24, 2010 at 12:12pmSo if i eliminate C first would the resulting two equations be:

(8/3A) + (8/3B) = 1

(1/A) + (1/B) = (-8/20)

???????

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