Posted by Jose on Friday, September 24, 2010 at 11:17am.
work done = (actual time worked) / (req'd time to finish a task)
'completed' work = 1
so let
A = time req'd for A
B = time req'd for B
C = time req'd for C
there will be 3 equations:
(8/3A) + (8/3B) = 1
(40/9B) + (40/9C) = 1
(20/7A) + (20/7C) = 1
use elimination method to solve the problem.
So if i eliminate C first would the resulting two equations be:
(8/3A) + (8/3B) = 1
(1/A) + (1/B) = (-8/20)
???????
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