geometry
posted by lilboo on .
find the value value of X
m<AOB=4x2, m<BOC=5x+10 m<COD=3x8

m<AOE = 180 and M<BOC and m<DOE are congruent angles
So
m<AOB + m<BOC + m<COD + m<DOE = 180
(4x2)+(5x+10)+(3x8)+(5x+10) = 180
17x+10=180
17x = 170
x = 170 
m<AOE = 180 and M<BOC and m<DOE are congruent angles
So
m<AOB + m<BOC + m<COD + m<DOE = 180
(4x2)+(5x+10)+(3x8)+(5x+10) = 180
17x+10=180
17x=170
x=10