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physics

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Consider a projectile fired horizontally from a cliff of a given height. With what speed must it be fired so that it makes a 45 degree angle with the ground when it hits

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    It hits ground with 45° angle when the vertical velocity, vy, is the same as the horizontal velocity, vx, which equals u (initial velocity) if the projectile is fired horizontally and ignoring air-resistance.

    vx=u

    Let H=given height of cliff
    vy²-0²=2gH
    vy²=2gH
    since vy=u,
    u²=2gH
    u=√(2gH)

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