Posted by Ligu on Friday, September 24, 2010 at 3:43am.
It hits ground with 45° angle when the vertical velocity, vy, is the same as the horizontal velocity, vx, which equals u (initial velocity) if the projectile is fired horizontally and ignoring air-resistance.
vx=u
Let H=given height of cliff
vy²-0²=2gH
vy²=2gH
since vy=u,
u²=2gH
u=√(2gH)
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