Posted by flame on Friday, September 24, 2010 at 1:46am.
Use bernoulli's equation
p+ρV²+ρgh=constant
for each of the sections.
p=pressure
ρ=density
V=velocity
The ρgh term can be neglected if the pipe is horizontal.
The continuity equation gives
A1V1=A2V2, where
V1, V2, A1 and A2 are the velocities and cross sectional areas of the corresponding sections.
So we have two unknowns V1 and V2, and two equations
p1+ρV1²=p2+ρV2² ...(1)
V1*A1=V2*A2 ....(2)
Solve for V1 and V2.
how do i convert the answer to kg/s
Flow is given by the product of the water velocity (m/s) and cross sectional area (m²), multiplied by the density ρ (1000 kg/m³).
or,
Q=A1*V1*ρ
Related Questions
physics - A horizontal pipe 17.00 cm in diameter has a smooth reduction to a ...
Physics - A horizontal pipe, 10 cm in diameter, has a smooth reduction to a pipe...
physics - What is the pressure change in water going from a 3.0- cm-diameter ...
physic - Water flows through a 4.0-cm-diameler horizontal pipe ata speed uf 1.3 ...
physics - 1.)Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. How...
physics - 1.)Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. How...
physics - 1.) Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. ...
physics - 1.) Water flows from a 2 cm diameter pipe, at a speed of 0.35m/sec. ...
physics - A large water tank has an inlet pipe and an outlet pipe. The inlet ...
physics - A horizontal pipe of diameter 0.845 m has a smooth constriction to a ...
For Further Reading
