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October 20, 2014

October 20, 2014

Posted by **flame** on Friday, September 24, 2010 at 1:46am.

- physics -
**MathMate**, Friday, September 24, 2010 at 10:02amUse bernoulli's equation

p+ρV²+ρgh=constant

for each of the sections.

p=pressure

ρ=density

V=velocity

The ρgh term can be neglected if the pipe is horizontal.

The continuity equation gives

A1V1=A2V2, where

V1, V2, A1 and A2 are the velocities and cross sectional areas of the corresponding sections.

So we have two unknowns V1 and V2, and two equations

p1+ρV1²=p2+ρV2² ...(1)

V1*A1=V2*A2 ....(2)

Solve for V1 and V2.

- physics -
**flame**, Sunday, September 26, 2010 at 8:57pmhow do i convert the answer to kg/s

- physics -
**MathMate**, Monday, September 27, 2010 at 9:44amFlow is given by the product of the water velocity (m/s) and cross sectional area (m²), multiplied by the density ρ (1000 kg/m³).

or,

Q=A1*V1*ρ

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