Posted by **JULIET** on Friday, September 24, 2010 at 1:37am.

A rock is dropped from rest into a well. The sound of the splash is heard 2.40 s after the rock is

released from rest. (a) How far below the top of the well is the surface of the water? The speed of sound

in air (at the ambient temperature) is 336 m/s. (3p) (b) What If? If the travel time for the sound is

neglected, what percentage error is introduced when the depth of the well is calculated?

- PHYSICS -
**MathMate**, Friday, September 24, 2010 at 9:39am
Speed of sound, s=336 m/s

depth, x m

initial velocity = 0 =u m/s

total time, T = 2.4 seconds

time to descendm, t= 2.4 - x/s

x=ut+(1/2)gt²

t+x/s=2.4

t+(ut+(1/2)gt²)/s=2.4

Solve for t. I get t=2.32(approx.)

x=ut+(1/2)gt²

=26.4 m (approx.)

For part b, calculate x when t=2.4 and compare with part a.

- PHYSICS -
**katleho**, Thursday, September 29, 2016 at 12:26pm
I get 28.2m

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