3x^2-x=7

can u help me with plz

3x²-x=7

√x √7
3x-x=√7
2x=√7
x=√7/2 or x=1.32

There are no rational factors for the zeroes.

So solve by the quadratic formula:
3x²-x=7
3x²-x-7 = 0
x=(1±√(1+84))/6
=(1±√(85))/6
=-1.37 or 1.70 approx.

Of course! I can help you solve the equation 3x^2 - x = 7. To solve this equation, you need to isolate the variable x. Here's how you can do it step by step:

Step 1: Move the constant term to the right side of the equation by adding 7 to both sides:
3x^2 - x + 7 = 7 + 7
3x^2 - x + 7 = 14

Step 2: Rearrange the equation so that it is in standard quadratic form (ax^2 + bx + c = 0) by combining like terms:
3x^2 - x - 7 = 0

Step 3: To factorize this quadratic equation, look for two numbers that multiply to give the product of the square coefficient (3) and the constant term (-7), which is -21, and add up to give the coefficient of the linear term (-1). In this case, the numbers are -7 and 3:
3x^2 - 7x + 3x - 7 = 0

Step 4: Group the terms so that a common factor can be factored out:
(3x^2 - 7x) + (3x - 7) = 0

Step 5: Factor out the greatest common factor from each group:
x(3x - 7) + 1(3x - 7) = 0

Step 6: Notice that (3x - 7) is a common factor in both terms. Factor it out:
(3x - 7)(x + 1) = 0

Step 7: Set each factor equal to zero and solve for x:
3x - 7 = 0 or x + 1 = 0

Step 8: Solve each equation separately:
For 3x - 7 = 0, add 7 to both sides and divide by 3:
3x = 7
x = 7/3

For x + 1 = 0, subtract 1 from both sides:
x = -1

Therefore, the solutions to the equation 3x^2 - x = 7 are x = 7/3 and x = -1.