A) A partly full paint can has 0.747 U.S. gallons of paint left in it. What is the volume of the paint in cubic meters?

I got the answer as 0.00283 cm^3

B) If all the remaining paint is used to coat a wall evenly (wall area = 11.7 m2), how thick is the layer of wet paint?

Im not sure how to solve part B) !

Part A is correct, but the unit should be m³ (cubic metre).

For part B, consider the 0.00283 m³ of paint is used to make a huge but flat box with the same volume, then
11.7 m²*thickness = 0.00283 m³.
Solve for thickness.

0.747 gallons * (1 ft^3)/(7.48 gallons) *(0.3048 m/ft)^3 = ___ m^3

b) the volume in m^3 equals the area coverage {in m^2} times the paint coating thickness, in meters.

To solve part B, we need to use the volume of paint calculated in part A and the formula for the volume of a cylinder.

B) First, let's convert the volume of paint from gallons to cubic meters. We will use the conversion factor: 1 gallon = 0.00378541 cubic meters.

Given that the paint can contains 0.747 U.S. gallons of paint, we can calculate the volume in cubic meters as follows:

Volume = 0.747 gallons * 0.00378541 cubic meters/gallon
Volume ≈ 0.0028248 cubic meters

So, the volume of paint is approximately 0.0028248 cubic meters.

Now, we can use the formula for the volume of a cylinder to determine the thickness of the paint layer when it is evenly coated on a wall.

Volume of a cylinder = π * radius^2 * height

In this case, the wall area is given as 11.7 m^2. Assuming the wall is completely covered, the paint will evenly spread over this area. Therefore:

11.7 m^2 * thickness of paint layer = 0.0028248 cubic meters

To solve for the thickness of the paint layer, divide both sides of the equation by 11.7 m^2:

Thickness of paint layer = 0.0028248 cubic meters / 11.7 m^2
Thickness of paint layer ≈ 0.000241 m

So, the thickness of the wet paint layer on the wall would be approximately 0.000241 meters.