Posted by **Liana** on Thursday, September 23, 2010 at 9:12pm.

At 1 pm two trains, traveling toward each other leave from towns that are 312 km apart. One train averages at most 82km/h and the other at most 74km/h. What is the earliest possible time for them to meet?

Please help me solve this. I'm not exactly sure how to set up the equation or inequality.

- Math -
**Reiny**, Thursday, September 23, 2010 at 10:29pm
For these kind of questions you have to ask yourself,

which of my quantities are equal so I can make an equation?

When the meet, will they not have travelled the same time? So the times are equal

let the distance covered by the faster train be x km

then the distance covered by the slower train is 312-x km

time taken by faster train = x/82

time taken by slower train = (312-x)/72

so ..

x/82 = (312-x)/72

crossmultiply and simplify to get

x =166.13 km

so time is 166.13/82 = 2.026 hours

- Math -
**joseph**, Sunday, June 10, 2012 at 12:33pm
Simplify please...thnks

X/50=(312-X)60

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