Posted by **Cheyenne** on Thursday, September 23, 2010 at 8:46pm.

A sample of air contains 21.9ìg/m3 of beryllium dust. How many atoms of beryllium are present in a room with dimensions of 8 feet by 12.3 feet by 18.3 feet? Answer in units of atoms.

- Chemistry -
**DrBob222**, Thursday, September 23, 2010 at 9:14pm
I would change feet to meters for all three dimensions, then L x W x H of the room (in meters) will give you the volume in cubic meters. volume x concn Be dust (the 21.9 something g/m^3) will give you grams Be dust. Divide by atomic mass to arrive at moles, then remember there are 6.022 x 10^23 atoms in a mole.

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