It takes 56 mL of 0.124 M KOH to neutralize 45.4 mL of H2SO4 solution. What is the concentration of the H2SO4 solution? Answer in units of moles/liter
Write the equation and balance it.
Find mols KOH. moles = M x L
Convert moles KOH to moles H2SO4 using the coefficients in the balanced equation. Then M H2SO4 = moles/L
To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry and the equation for the neutralization reaction between KOH and H2SO4.
The balanced equation for the reaction is:
2 KOH + H2SO4 → K2SO4 + 2 H2O
First, let's determine the number of moles of KOH used in the reaction. We can use the given volume and concentration of KOH.
Moles of KOH = volume (in liters) × concentration
= 56 mL × (1 L / 1000 mL) × 0.124 moles/L
= 0.007 moles
According to the balanced equation, the stoichiometric ratio between KOH and H2SO4 is 2:1. Therefore, the number of moles of H2SO4 in the reaction is also 0.007 moles.
Next, let's calculate the concentration of H2SO4 in the solution.
Concentration of H2SO4 = moles of H2SO4 / volume of H2SO4 (in liters)
= 0.007 moles / 45.4 mL × (1 L / 1000 mL)
≈ 0.000154 moles/L
Therefore, the concentration of the H2SO4 solution is approximately 0.000154 moles/L or 0.154 M.