What is the limit, as x goes to 0, of [sinx(1-cosx)]/(2x^2)?
write it as
lim (1/2)(sinx/x)(1-cosx)/x
x ---> 0
you should have learned that
lim sinx/x = 1 and lim (1-cosx)x =0
so the above is
(1/2)(1)(0) = 0
lim (1/2)(sinx/x)(1-cosx)/x
x ---> 0
you should have learned that
lim sinx/x = 1 and lim (1-cosx)x =0
so the above is
(1/2)(1)(0) = 0