Posted by **Jon** on Thursday, September 23, 2010 at 7:31pm.

A cheetah can maintain its maximum speed of 120 km/hr for 38 seconds. What minimum distance must a gazelle running 74 km/hr be ahead of the cheetah to escape?

A) 417.2 m

B) 3778 m

C) 624.3 m

D) 485.6 m

E) 1748 m

- Physics -
**bobpursley**, Thursday, September 23, 2010 at 7:33pm
at t=38, one wants the separation be 1 meter.

distance(38)=speedgazelle*38-speedcheeta(38)+intialseparation

change the speeds to m/s, then

1=xxx*38-YYY*38+initialseparation

solve for separation

- Physics -
**Jon**, Thursday, September 23, 2010 at 7:39pm
so, with that i got 484.26.

they obviously solved for separation to be 0 at 38s, which doesn't make sense because the gazelle would die.. but do you think d then is the right answer?

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