Posted by **Amedus** on Thursday, September 23, 2010 at 7:07pm.

A stone is thrown vertically upward with a speed of 12.0 m/s from the edge of a cliff 85.0 m high (Fig. 2-34).

(a) How much later does it reach the bottom of the cliff?

(b) What is its speed just before hitting?

(c) What total distance did it travel?

- Physics -
**bobpursley**, Thursday, September 23, 2010 at 7:17pm
It is the same equations as always:

d=Vi*t-1/2 g t^2

Vf=Vi+gt

Now for total distance, you will have to calculate the height it reaches at the top (when vf is zero). Double that, add to height of cliff.

## Answer this Question

## Related Questions

- science - A stone is thrown vertically upward with a speed of 11.0 m/s from the ...
- physics - a stone is thrown vertically upward with a speed of 10.5 m/s from the ...
- physics - A stone is thrown vertically upward with a speed of 10.0 m/s from the ...
- physics - A stone is thrown vertically upward with a speed of 11.5 m/s from the ...
- physics - A stone is thrown vertically upward with a speed of 11.5 m/s from the...
- physics - A stone is thrown vertically upward with a speed of 11.5 m/s from the ...
- physics for physical science - A stone thrown vertically upwards with a speed ...
- physics - A stone is thrown vertically upward with a speed of 14.0 m/s from the ...
- physics - A stone is thrown horizontally at a speed of 4.8 m/s from the top of a...
- Physics - A stone is thrown straight upward with a speed of 12 m/s from the edge...

More Related Questions