Posted by **Ed** on Thursday, September 23, 2010 at 5:23pm.

Find the quotient function f/g for f(x)=sqr(x+1) and g(x)= sqr( x-1).

My Answer:

sqr(x+1)/sqr( x-1)

sqr(x^2-1)/ (x-1)

However, I also have to state the restrictions to the domain and range, which I do not know how to do. Could someone please help me? Thanks.

- Math -
**Reiny**, Thursday, September 23, 2010 at 6:42pm
your answer is correct.

for the restriction, the denominator cannot be zero, so x≠1

also the inside of the square root cannot be negative,

this will happen when -1 ≤ x ≤ +1

so the domain is x ≤ -1 OR x > 1

as x gets +large, the expression approaches 1

as x gets -large, the expression approaches -1

range: y >1 OR y < -1

## Answer this Question

## Related Questions

- Math - Find the quotient function f/g for f(x)=sqr(x+1) and g(x)= sqr( x-1). My ...
- math - I have a question I have been working on since yesterday and I am not ...
- Algebra2/Trig - sqr(x^2-4)+(x^2)/x^2+1 I got ((x^2+1)*sqr(x^2-4)+x^2)/x^2+1 But ...
- algebra 1 - sqr 10 times sqr 16 over sqr 5
- TRIG - Given that tanx = 1/sqr(15) and secx -4/sqr(15) find the value of sinx
- Math - Perform the indicated operations and simplify i^37 sqr-12 x sqr-15
- geometry - Rays PQ and QR are perpindicular. Point S lies i the interior of ...
- algebra 1 - 1 over 2 sqr 32 times sqr 2 simplify the expression
- algebra 1 - sqr 9 over sqr 49 simplify the expression
- algebra 1 - sqr 49 over sqr 4 simplify the expression

More Related Questions