A swimmer is heading straight for the other shore of a river with a velocity of vs=0.7 m/s relative to the water, but is carried away by the current, which has a velocity of vr=0.3 m/s. It takes her 20.3 s to get across. How far downstream does she end up?
This is what I did but it is wrong. Can someone help me?
20.3/0.6=29
distance=velocityriver*time
This is vastly different from what you did, and I don't understand what you did.
Vs=0.7 relative to water,Vr=0.3&t=20.3sec then,Vsr=Vm-Vr,0.7+0.3=1m/s. V=s/t ,s=vt ,20.3m
To solve this problem, you need to consider the relative velocities of the swimmer and the current and then use the formula d = v * t to find the distance.
Let's break down the problem step by step:
1. First, determine the swimmer's velocity relative to the ground. To find this, you need to subtract the velocity of the current from the swimmer's velocity. In this case, the swimmer's velocity relative to the ground is: vs - vr = 0.7 m/s - 0.3 m/s = 0.4 m/s.
2. Next, multiply the swimmer's velocity relative to the ground by the time it takes for her to cross the river. So, the distance she crosses is: 0.4 m/s * 20.3 s = 8.12 meters.
3. Finally, find the distance downstream the swimmer ends up by multiplying the velocity of the current by the time taken to cross. In this case, the distance downstream is: vr * t = 0.3 m/s * 20.3 s = 6.09 meters.
Therefore, the swimmer ends up 6.09 meters downstream from her starting point.