physics
posted by rabiya .
A certain copper wire has a resistance of 12.0 \Omega.At what point along its length must the wire be cut so that the resistance of one piece is 5.0 times the resistance of the other?

resistance is proportional to length, so the lengths have to be in the ratio of 1:4, so the cut must be at 1/5 the length, giving you lengths of 1/5 and 4/5 the length. Actual resistances are 10/5 ohms and 40/5 ohms, or R1=2 ohms and R2=8