Posted by **Sam** on Thursday, September 23, 2010 at 2:34pm.

A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on top of the cliff 9.2 s after it is fired, find the initial velocity of the projectile (magnitude and direction). Neglect air resistance. Also calculate the angle

- Physics -
**bobpursley**, Thursday, September 23, 2010 at 2:44pm
Well, you have some algebra ahead.

Vertical:

155=VsinTheta*t-4.9t^2

Horizontal:

195=VcosTheta*t

you are given t.

So you have two equations, two unknowns.

Here is what I suggest. Put both equations in the form of

V*trigfunction=some number

then square both sides.

add the equations, you should get something like this:

V^2(cosTheta ^2 + sinTheta ^2)=number^2

well, you know the ( ) is 1, which allows you to solve for V. Then substitute back to solve for theta.

Have fun.

## Answer this Question

## Related Questions

- Physics - A projectile is launched from ground level to the top of a cliff which...
- physics - A projectile is launched from ground level to the top of a cliff which...
- physics - A projectile is launched from ground level to the top of a cliff which...
- physics - A projectile is launched from ground level to the top of a cliff which...
- Physics - A projectile is launched from ground level to the top of a cliff which...
- math - A projectile is launched from ground level to the top of a cliff which is...
- physics - A projectile is fired at an angle of 30ᵒ above the horizontal ...
- physics - a projectile is fired at an angle of 27 above the horizontal from the ...
- physics - projectile is launched horizontally from edge of cliff 20 m high with ...
- Physics -.- - A projectile is shot horizontally at 220 m/s from the top of a 620...

More Related Questions