Posted by Holly on .
A car travels along a roadwith a speed of v=25 m/s (about 50 mi/h). The coefficient of kinetic frictionbetween the tires and the pavement is mu k=.55.
a). If the driver applies the brakes and the tires "lock up" so that they skid along the road, how far does the car travel before it comes to a stop?
b). If the same car is traveling downhill along a roas that makes an angle of 12 degrees, how much does the car's stopping distance increase?
c). What is the stopping disance on an uphill road with theta =12 degrees?
I need to show my work and am totally lost.
The answer if 2.02*2012.3165461