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November 25, 2014

November 25, 2014

Posted by **Scott** on Thursday, September 23, 2010 at 11:02am.

I know the answer is 1/17 e^x sin4x - 4/17 e^x cos4x + C but I don't know how to solve it out.

- Calculus -
**MathMate**, Thursday, September 23, 2010 at 4:01pmUse integration by parts:

I=∫e^{x}sin(4x)dx

=e^{x}sin(4x)-4∫e^{x}cos(4x)dx

=e^{x}sin(4x)-4e^{x}cos(4x)-16∫e^{x}sin(4x)dx

=e^{x}sin(4x)-4e^{x}cos(4x)-16I

Solve for I to get the above results.

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