Use the Quadratic Formula to solve the equation: 5x^2 - 6x - 8=0
-.51,1.71?
plug the values you found for x and see if it equals to zero.
http://www.purplemath.com/modules/quadform.htm
Is the answer no solution?
i think the answer will be , 2 & -.8
Thanks
To solve the quadratic equation 5x^2 - 6x - 8 = 0 using the quadratic formula, follow these steps:
Step 1: Identify the coefficients of the equation. In this case, the coefficients are:
a = 5
b = -6
c = -8
Step 2: Write down the quadratic formula. The quadratic formula is given as:
x = (-b ± √(b^2 - 4ac)) / (2a)
Step 3: Substitute the values of a, b, and c into the quadratic formula:
x = (6 ± √((-6)^2 - 4 * 5 * -8)) / (2 * 5)
Step 4: Simplify the expression inside the square root:
x = (6 ± √(36 + 160)) / 10
x = (6 ± √196) / 10
x = (6 ± 14) / 10
Step 5: Simplify further by finding both possible solutions:
x1 = (6 + 14) / 10 = 20 / 10 = 2
x2 = (6 - 14) / 10 = -8 / 10 = -0.8
So, the solutions to the quadratic equation 5x^2 - 6x - 8 = 0 are x = 2 and x = -0.8. Therefore, the answer you provided (-0.51, 1.71) seems to be incorrect.