John and Paul work together at a music store. In one afternoon, they sold a total of 41
CDs. If Paul sold 9 more CDs than John, how many CDs did John sell?
Math:
If we take away 9 CDs, then they sold equal quantities, namely (41-9)/2=16 each.
So John sold 16, and Paul sold 16+9=25 CDs.
Algebra:
Let x=number of CD's sold by John, then Paul sold x+9.
Equate total:
x+x+9=41
2x=41-9
2x=32
x=16 (John)
x+9=25 (Paul)
thank you
To find out how many CDs John sold, we need to set up an equation based on the given information. Let's assume John sold X number of CDs.
We know that Paul sold 9 more CDs than John. So, the number of CDs Paul sold can be represented as X + 9.
The total number of CDs sold by both of them is given as 41. Therefore, we can write the equation as:
X + (X + 9) = 41
Simplifying this equation, we get:
2X + 9 = 41
Next, we can subtract 9 from both sides of the equation to isolate 2X:
2X = 41 - 9
2X = 32
Finally, we divide both sides of the equation by 2 to find the value of X:
X = 32 / 2
X = 16
Therefore, John sold 16 CDs.