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March 4, 2015

March 4, 2015

Posted by **curtina blue** on Wednesday, September 22, 2010 at 10:04pm.

d=vt+1/2at with a a square route of 2

A bicycle traveling at a velocity of 4.5 meters per second accelerates down a hill at a constant rate of 0.4 meters per second squared for 12 seconds. What is the distance, in meters, that the bicycle travels?

- algebra -
**Anonymous**, Monday, November 15, 2010 at 1:35pmv=4.5m/s

a=0.4m/s

t=12s

d= vt+1/2at^2

d= 4.5(12) + 1/2(0.4)(12)^2

d= 54+28.8

d= 82.8m

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