Homework Help: Physics

Posted by chuck on Wednesday, September 22, 2010 at 9:36pm.

A uniform electric field of magnitude 395 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 3.40 cm. What is the work done by the field on the electron? What is the change in potential energy associated with the electron? What is the velocity of the electron?

Physics - bobpursley, Wednesday, September 22, 2010 at 9:37pm
Work=Eqd

velocity= work=1/2 mv^2
1/2 mv^2=Eqd solve for v

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