Tuesday

March 31, 2015

March 31, 2015

Posted by **timmy** on Wednesday, September 22, 2010 at 8:48pm.

for y= absolute value of f(x) does the derivitive exist at x=0 and explain why.

- Hard Calculus -
**MathMate**, Wednesday, September 22, 2010 at 9:17pmf(x)=|x²-2x|

=x²-2x (-∞,0]U[2,∞)

=-(x²-2x) (0,2)

f'(x)

=2x-2 (-∞,0)U(2,∞)

=-(2x-2) (0,2)

f'(0-)=-2

f'(0+)=2

Therefore the derivative is not continuous at x=0, and therefore f'(0) does not exist.

See:

http://img683.imageshack.us/img683/654/1285202904.png

**Answer this Question**

**Related Questions**

12th grade calculus - Let f(x)=[x^3-9x] [] --- absolute value a. does f'(x) ...

Calculus - Find the absolute maximum value and the absolute minimum value, if ...

math calculus - Find the absolute extrema of the function on the closed interval...

Calculus - Find the absolute maximum value and the absolute minimum value, if ...

Calculus urgent help - evaluate the limit as x approaches infinity for the ...

math - Find the absolute maximum value and the absolute minimum value, if any, ...

Math - Find the absolute maximum value and the absolute minimum value, if any, ...

Math - Find the absolute maximum value and the absolute minimum value, if any, ...

math - Find the absolute maximum value and the absolute minimum value, if any, ...

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...