Posted by timmy on Wednesday, September 22, 2010 at 8:48pm.
f(x)= xsquared 2x
for y= absolute value of f(x) does the derivitive exist at x=0 and explain why.

Hard Calculus  MathMate, Wednesday, September 22, 2010 at 9:17pm
f(x)=x²2x
=x²2x (∞,0]U[2,∞)
=(x²2x) (0,2)
f'(x)
=2x2 (∞,0)U(2,∞)
=(2x2) (0,2)
f'(0)=2
f'(0+)=2
Therefore the derivative is not continuous at x=0, and therefore f'(0) does not exist.
See:
http://img683.imageshack.us/img683/654/1285202904.png
Answer This Question
Related Questions
 12th grade calculus  Let f(x)=[x^39x] []  absolute value a. does f'(x) ...
 Calculus  Find the absolute maximum value and the absolute minimum value, if ...
 calculus  Find the absolute extrema of the function (if any exist) on each ...
 math calculus  Find the absolute extrema of the function on the closed interval...
 Calculus  Find the absolute maximum value and the absolute minimum value, if ...
 Calculus urgent help  evaluate the limit as x approaches infinity for the ...
 math  Find the absolute maximum value and the absolute minimum value, if any, ...
 Math  Find the absolute maximum value and the absolute minimum value, if any, ...
 Math  Find the absolute maximum value and the absolute minimum value, if any, ...
 math  Find the absolute maximum value and the absolute minimum value, if any, ...
More Related Questions