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A mixture of CuSO4 and CuSO4·5 H2O has a mass of 1.235 g. After heating to drive off all the water, the mass is only 0.830 g. What is the mass percent of CuSO4·5 H2O in the mixture?

  • Chemistry -

    Mass of H2O expelled = 1.235-0.830=0.405 g

    RMM of 5H2O = 5*(2*1+16)=90

    RMM of crystalline CuSO4
    =63.55+32+4*16 + 90

    Therefore, by proportion, mass of crystalline CuSO4.5H2O
    Mass percentage of CuSO4.5H2O
    =mass of CuSO4.5H2O / total mass

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