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A cannon is fired from a cliff 200 m high downward at an angle of 30o with respect to the horizontal. If the muzzle velocity is 34 m/s, what is its speed (in m/s) when it hits the ground?

  • physics - ,

    Ignoring air-resistance, equate energies:

    (PE+KE)initial = (PE+KE)final

    mgh+(1/2)mu² = (1/2)mv²
    Solve for v.

    I get approx. 71 m/s.

  • physics - ,

    thank you so much!

  • physics - ,

    You're welcome!

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