The height of an object thrown upward with an initial velocity of 96 feet per second is given by the formula h = -16t2 + 96t, where t is the time in seconds. How long will it take the object to reach a height of 144 feet?

To find the time it takes for the object to reach a height of 144 feet, we need to solve the equation h = 144 for t.

Substituting the given equation h = -16t^2 + 96t into the equation h = 144, we get:

-16t^2 + 96t = 144

Now we have a quadratic equation. To solve it, we need to rearrange the equation to be in the form of ax^2 + bx + c = 0. Let's rearrange the equation:

-16t^2 + 96t - 144 = 0

Next, we can simplify the equation by dividing the entire equation by -16(take out the common factor of -16):

t^2 - 6t + 9 = 0

Now we have the quadratic equation in the form of t^2 - 6t + 9 = 0. To solve this quadratic equation, we can factorize or use the quadratic formula.

Let's try to factorize the equation:

(t - 3)(t - 3) = 0

From this, we can see that t = 3.

Therefore, it will take the object 3 seconds to reach a height of 144 feet.

let h=144

-16t^2 + 96t=144
and solve for t