What weight of copper(II) oxide, CuO, would theoretically be produced from 1.623 grams of copper? (mol. masses Cu = 63.55; O = 16.00)
1.623 g is how many mols.
1.623/atomic mass Cu.
1 mole CuO = 1 mole Cu; therefore, moles CuO is same as mols Cu.
Then moles CuO x molar mass CuO = grams CuO.
Weigh of testube of bung =16.8g and copper 2 oxide
To determine the weight of copper(II) oxide (CuO) that would theoretically be produced from 1.623 grams of copper (Cu), we need to follow these steps:
Step 1: Convert the mass of copper (Cu) to moles.
To convert the mass to moles, we need to use the molar mass of copper (Cu).
Molar mass of copper (Cu) = 63.55 g/mol
Number of moles of copper (Cu) = Mass of copper (Cu) / Molar mass of copper (Cu)
= 1.623 g / 63.55 g/mol
Step 2: Use the balanced chemical equation to determine the stoichiometry between copper (Cu) and copper(II) oxide (CuO).
According to the balanced chemical equation for the reaction between copper (Cu) and oxygen (O2):
2Cu + O2 -> 2CuO
From the equation, we can see that 2 moles of copper (Cu) react to produce 2 moles of copper(II) oxide (CuO).
Step 3: Apply the stoichiometry to find the moles of copper(II) oxide (CuO).
Since the stoichiometry tells us that 2 moles of copper (Cu) react to produce 2 moles of copper(II) oxide (CuO), we can say that:
Number of moles of copper(II) oxide (CuO) = Number of moles of copper (Cu)
Step 4: Convert the moles of copper(II) oxide (CuO) to mass.
To convert the number of moles to mass, we need to use the molar mass of copper(II) oxide (CuO).
Molar mass of copper(II) oxide (CuO) = Molar mass of copper (Cu) + Molar mass of oxygen (O)
= 63.55 g/mol + 16.00 g/mol
Weight of copper(II) oxide (CuO) = Number of moles of copper(II) oxide (CuO) * Molar mass of copper(II) oxide (CuO)
Now, let's calculate the weight of copper(II) oxide (CuO) produced:
Number of moles of copper (Cu) = 1.623 g / 63.55 g/mol = 0.0255 mol
Number of moles of copper(II) oxide (CuO) = 0.0255 mol
Molar mass of copper(II) oxide (CuO) = 63.55 g/mol + 16.00 g/mol = 79.55 g/mol
Weight of copper(II) oxide (CuO) = 0.0255 mol * 79.55 g/mol = 2.03 grams
Therefore, theoretically, 2.03 grams of copper(II) oxide (CuO) would be produced from 1.623 grams of copper (Cu).
To find the theoretical weight of copper(II) oxide (CuO) produced from a given amount of copper (Cu), we can use stoichiometry and balanced chemical equation. Here's how to approach this problem:
Step 1: Write the balanced chemical equation:
Cu + O2 -> CuO
Step 2: Determine the molar mass of copper and oxygen:
Molar mass of Cu = 63.55 g/mol
Molar mass of O = 16.00 g/mol
Step 3: Calculate the number of moles of Cu from the given mass:
moles of Cu = given mass of Cu / molar mass of Cu
moles of Cu = 1.623 g / 63.55 g/mol
Step 4: Use the mole ratio from the balanced equation to find the moles of CuO:
From the balanced equation, the mole ratio between Cu and CuO is 1:1. This means that 1 mole of Cu will produce 1 mole of CuO.
moles of CuO = moles of Cu
Step 5: Convert moles of CuO to grams using the molar mass of CuO:
mass of CuO = moles of CuO * molar mass of CuO
Substituting the values:
mass of CuO = moles of Cu * molar mass of CuO
Now, let's plug in the values and calculate the mass of CuO:
moles of Cu = 1.623 g / 63.55 g/mol
moles of Cu = 0.0255 mol
mass of CuO = 0.0255 mol * (63.55 g/mol + 16.00 g/mol)
mass of CuO = 0.0255 mol * 79.55 g/mol
mass of CuO ≈ 2.03 grams
Therefore, theoretically, 2.03 grams of copper(II) oxide (CuO) would be produced from 1.623 grams of copper.