Perform the indicated division

2x^2-7x-13/x-5

See:

http://www.purplemath.com/modules/polydiv2.htm

Please make an attempt and post your answer for checking.

thanks for the link...It helped me a lot

To perform division of polynomials, we need to use long division. Here's a step-by-step process on how to perform the indicated division of the polynomial (2x^2 - 7x - 13) by (x - 5):

Step 1: Divide the first term of the dividend (2x^2) by the first term of the divisor (x). The quotient becomes the first term of the quotient.

2x^2 / x = 2x

Step 2: Multiply the divisor (x - 5) by the quotient (2x) obtained in step 1. Write the result below the dividend (2x^2 - 7x - 13).

2x * (x - 5) = 2x^2 - 10x

Step 3: Subtract the result obtained in step 2 from the original dividend.

(2x^2 - 7x - 13) - (2x^2 - 10x) = -7x + 10x - 13 = 3x - 13

Step 4: Bring down the next term from the dividend (-13).

3x - 13

Step 5: Repeat steps 1-4 with the new dividend (3x - 13).

Step 6: Divide the first term of the new dividend (3x) by the first term of the divisor (x). The quotient becomes the next term of the quotient.

3x / x = 3

Step 7: Multiply the divisor (x - 5) by the quotient (3) obtained in step 6. Write the result below the new dividend (3x - 13).

3 * (x - 5) = 3x - 15

Step 8: Subtract the result obtained in step 7 from the new dividend.

(3x - 13) - (3x - 15) = 2

We have reached the point where further division is not possible since the degree of the new dividend (2) is less than the degree of the divisor (x - 5). The quotient is obtained by combining all the terms from the previous quotient.

Therefore, the division of (2x^2 - 7x - 13) by (x - 5) is equal to 2x + 3, with a remainder of 2.