How do I solve the quadratic equation 3x^2 + 5x + 2 =0 Please explain the steps-I really don't get this
3x^2 + 5x + 2 =0 3x²+3x +2x+2 = 0 3x(x+1) + 2(x+1) = 0 (3x+2)(x+1)=0 So 3x+2=0 or x+1=0 Solve for x in both cases.
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