Posted by Jamie on Tuesday, September 21, 2010 at 5:46pm.
I found this example on purplemath
You coul use this and apply knowledge.
This is the original equation. x2 + 6x – 7 = 0
Move the loose number over to the other side. x2 + 6x = 7
Take half of the x-term (that is, divide it by two) (and don't forget the sign!), and square it. Add this square to both sides of the equation.
Convert the left-hand side to squared form. Simplify the right-hand side. (x + 3)2 = 16
Square-root both sides. Remember to do "±" on the right-hand side. x + 3 = ± 4
Solve for "x =". Remember that the "±" gives you two solutions. Simplify as necessary. x = – 3 ± 4
= – 3 – 4, –3 + 4
= –7, +1
Thank you
you're welcome!
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