When Maggie applies the brakes of her car,the car slows uniformly from 15.4 m/s to 0m/s in 2.41 s.How far ahead of a stop sign must she apply her brakes in order to stop at the sign?Answer in units of m.

speed = distance/ time

distance=(speed)*(time)
=(15.4 m/s)*(2.41s)

To find the distance ahead of the stop sign where Maggie must apply her brakes, we can use the equation of motion that relates distance, initial velocity, final velocity, and time.

The equation we'll use is:

distance = (initial velocity + final velocity) / 2 * time

Given:
Initial velocity (u) = 15.4 m/s
Final velocity (v) = 0 m/s
Time taken (t) = 2.41 s

Plugging the values into the equation:

distance = (15.4 m/s + 0 m/s) / 2 * 2.41 s

Simplifying:

distance = 15.4 m/s / 2 * 2.41 s

distance = (15.4 * 2.41) / 2 m

distance ≈ 18.597 m

Therefore, Maggie must apply her brakes approximately 18.6 meters ahead of the stop sign in order to stop at the sign.