Posted by **Stanley** on Tuesday, September 21, 2010 at 5:24pm.

A chain composed of four identical links is suspended by a rope and does not move. How many force vectors would be drawn on the free body diagram of each link and which direction would they point?

My answer:

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FIRST LINK (top): Upward force from rope (tension), downward normal force from link 2 (below), and downward force from earth (weight)

SECOND LINK: Upward normal force from link 1 (above), downward normal force from link 3 (below), and downward force from earth (weight)

THIRD LINK: Upward normal force from link 2 (above), downward normal force from link 4 (below), and downward force from earth (weight)

FOURTH LINK (bottom): Upward normal force from link 3 (above), downward force from earth (weight)

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Magnitudes from largest to smallest:

Upward force from rope

Downward normal force on link 1 from link 2=Upward normal force on link 2 from link 1

Downward normal force on link 2 from link 3=Upward normal force on link 3 from link 2

Downward normal force on link 3 from link 4=Upward normal force on link 4 from link 3 = W4 = W3 = W2 = W1

(Where W4 = Weight of link 4, W3 = Weight of link 3, W2 = Weight of link 2, and W1= Weight of link 1, all of which are equivalent)

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^ Is all of that right?

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