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April 1, 2015

April 1, 2015

Posted by **Amy~** on Tuesday, September 21, 2010 at 4:53pm.

((x-3)(x+2))/((x-1)) < 0

I don't understand since theres x-1 in the denominator

- Math -
**Reiny**, Tuesday, September 21, 2010 at 5:13pmThe critical values are -2, 1 ,and 3 , with of course x ? 1

I then pick an arbitrary value in each of the regions and determine the sign of the answer, the actual answer does not matter.

e.g let x = -5

(-)(-)/(-1) < 0 , so x <-2 works

let x = 0 , a value between -2 and 1

(-3)(+).(-) > 0 , no good

let x = 2 , a value between 1 and 3

(-)(+)/(+) < 0 , good

let x = 5 , a value > 3

(+)(+)/(+) > 0 , no good

so

x < -2 OR 1 < x < 3

- Math -
**Amy~**, Tuesday, September 21, 2010 at 6:52pmso for this: (-)(-)/(-1) < 0 , so x <-2 works

you replace the 0 with -2 ? .

Also for this part let x = 5 , a value > 3

(+)(+)/(+) > 0 , no good

you had to change the sign because it was all positive?

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