Need help please. the once with the ( )

is my answer but i am not sure if it right.
Thanks for your help.

15. If the distance from a converging lens to the object is less than the focal length of the lens, the image will be
A. real, inverted, and larger than the object.
(B). real, inverted, and smaller than the object. ?
C. virtual, upright, and larger than the object.
D. virtual, upright, and smaller than the object.

If an object 18 millimeters high is placed 12 millimeters from a diverging lens and the
image is formed 4 millimeters in front of the lens, what is the height of the image?
(A). 6 millimeters C. 14 millimeters
B. 8 millimeters D. 22 millimeters

didn't I just do this?

If you did it wasn't for me :)

It didn't post.

15. The image in a magnifying glass is NOT real. http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/raydiag.html

correct on the second.

thank you

To answer the first question:

When the distance from a converging lens to the object is less than the focal length of the lens, the image formed is real, inverted, and larger than the object. The correct answer is (A) real, inverted, and larger than the object.

To determine the height of the image in the second question:
We can use the lens formula 1/f = 1/v - 1/u, where f is the focal length of the lens, v is the image distance, and u is the object distance.

Given:
Object height (h) = 18 mm
Object distance (u) = -12 mm (since the object is placed on the left side of the lens)
Image distance (v) = -4 mm (since the image is formed on the left side of the lens)

Using the lens formula: 1/f = 1/v - 1/u

Plugging in the given values: 1/f = 1/-4 - 1/-12

Simplifying the equation: 1/f = -1/4 + 1/12

Finding the common denominator and adding the fractions: 1/f = -3/12 + 1/12 = -2/12

Simplifying further: 1/f = -1/6

To find the height of the image (h'), we can use the magnification formula: h'/h = -v/u

Plugging in the given values: h'/18 = -(-4)/-12

Simplifying the equation: h'/18 = 4/12

Cross-multiplying: 12h' = 4 * 18

Solving for h': 12h' = 72

Dividing by 12: h' = 6

Therefore, the height of the image is 6 millimeters. The correct answer is (A) 6 millimeters.