a)How many grams of NH3 can be produced from 2.84mol of N2.

b)How many grams of H2 are needed to produce 14.86g of NH3?

balanced equation: 3H2+N2->2HN3

a) convert mol of N2 into mol of NH3 by the mole ratio

(look at the balanced equation for the coefficients of NH3 and NH2)
convert mol of NH3 to grams of NH3 by multiplying by the molar mass of NH3
(2.84mol of N2)(__mol NH3/__mol N2)(__g NH3/1mol NH3)

Try doing the other one on your own. Post your work if you need help! The key to doing these kind of the problems is UNITS. Notice all the units cancel out except for g of NH3!

a) To find the number of grams of NH3 produced from 2.84 mol of N2, we need to use the balanced equation provided.

The balanced equation states that 3 moles of H2 react with 1 mole of N2 to produce 2 moles of NH3.

Since the balanced equation relates moles, we need to convert 2.84 mol of N2 into moles of NH3.

Using the stoichiometry of the equation, we can set up a proportion:

(2.84 mol N2) / (1 mol N2) = (x mol NH3) / (2 mol NH3)

Cross-multiplying and solving for x will give us the number of moles of NH3 produced:

x = (2.84 mol N2) * (2 mol NH3) / (1 mol N2) = 5.68 mol NH3

Now, to convert the number of moles of NH3 into grams, we need to multiply by the molar mass of NH3. The molar mass of NH3 is 17.03 g/mol.

(5.68 mol NH3) * (17.03 g NH3/mol) = 96.84 g NH3

Therefore, 96.84 grams of NH3 can be produced from 2.84 mol of N2.

b) To find the number of grams of H2 needed to produce 14.86 g of NH3, we will use the same balanced equation.

Again, we will set up a proportion using the stoichiometry:

(x g H2) / (2 g NH3) = (14.86 g NH3) / (1 mol NH3) * (3 mol H2) / (2 mol NH3) * (2 g H2) / (1 mol H2)

Let's break down the calculation step by step:

Step 1: Convert grams of NH3 to moles of NH3:
(14.86 g NH3) / (17.03 g/mol) = 0.872 mol NH3

Step 2: Apply stoichiometry to find moles of H2:
0.872 mol NH3 * (3 mol H2) / (2 mol NH3) = 1.308 mol H2

Step 3: Convert moles of H2 to grams of H2:
1.308 mol H2 * (2.02 g/mol) = 2.64 g H2

Therefore, 2.64 grams of H2 are needed to produce 14.86 g of NH3.