Posted by Jamie on Tuesday, September 21, 2010 at 3:03pm.
d = Vo*t + 0.5at^2,
We have one Eq and 2 unknowns: Vo, & a.
Vo = at, a = Vo / t,
In the 1st Eq, substitute Vo / t for a:
d = Vo*t + 0.5(Vo/t)*t^2,
Simplify:
d = Vo*t + 0.5Vo*t,
195 = 9.2Vo + 0.5*9.2Vo,
195 = 9.2Vo + 4.6Vo,
195 = 13.8Vo,
Vo = 195 / 13.8 = 14.13 m/s = Initial
velocity.
Related Questions
physics - A projectile is launched from ground level to the top of a cliff which...
physics - A projectile is launched from ground level to the top of a cliff which...
physics - A projectile is launched from ground level to the top of a cliff which...
Physics - A projectile is launched from ground level to the top of a cliff which...
Physics - A projectile is launched from ground level to the top of a cliff which...
math - A projectile is launched from ground level to the top of a cliff which is...
physics - projectile is launched horizontally from edge of cliff 20 m high with ...
physics - a projectile is shot from the edge of a cliff h=145m above ground ...
physics - A projectile is launched off of a 18.6 m high cliff with a velocity ...
Physics - A projectile is shot from the edge of a cliff h = 225 m above ground ...
For Further Reading