Posted by **Jamie** on Tuesday, September 21, 2010 at 3:03pm.

A projectile is launched from ground level to the top of a cliff which is 195 m away and 155 m high. If the projectile lands on top of the cliff 9.2 s after it is fired, find the initial velocity of the projectile (magnitude and direction). Neglect air resistance.

- Physics -
**Henry**, Wednesday, September 22, 2010 at 10:39pm
d = Vo*t + 0.5at^2,

We have one Eq and 2 unknowns: Vo, & a.

Vo = at, a = Vo / t,

In the 1st Eq, substitute Vo / t for a:

d = Vo*t + 0.5(Vo/t)*t^2,

Simplify:

d = Vo*t + 0.5Vo*t,

195 = 9.2Vo + 0.5*9.2Vo,

195 = 9.2Vo + 4.6Vo,

195 = 13.8Vo,

Vo = 195 / 13.8 = 14.13 m/s = Initial

velocity.

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