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October 25, 2014

October 25, 2014

Posted by **Chelsea** on Tuesday, September 21, 2010 at 2:47pm.

So, I did this:

a(3)^2 + b(3) + c = 0

Solve: c = -12

For the point (4,2):

a(4)^2 + b(4) - 12 = 2

Solve: 16a + 4b = 14

I am not sure if I am doing this correctly and I am also stuck at the is point. Please help.

- Calculus -
**MathMate**, Tuesday, September 21, 2010 at 5:19pmc does not equal -12:

a(3)^2 + b(3) + c = 0

Solve: c = -9a - 3b (not -12)

For the given parabola, since the vertex is (3,0), and knowing that parabolas are symmetrical with respect to the vertex, we therefore have another point (2,2), the mirror image of (4,2) about x=3 passing through the vertex.

The three known points give rise to three equations with three unknowns (a,b,c). Solve for a,b and c.

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